Tim Streater wrote:

In article , Andy Burns
wrote:

Fredxx wrote:

You could simply have said, "the diameter of each core excluding
insulation"

Except it's not a diameter of 1.5mm, it's a cross-section of 1.5mm^2

So it's a core diameter of just under 1.4mm.

So solve 2r = (pi)r^2 and you will know what wire has a diameter
numerically equal to its CSA. I can't be bothered. But I think trial
and error iteration to two decimal places would be quicker than
remembering the formula for quadratic equations.



--

Roger Hayter