On Tue, 26 Jun 2018 09:05:15 +0100, The Natural Philosopher
wrote:

snip

My point is that once te tyre is on and deforming, that relationship has
no validity or meaning. I applies to circle only. And the flatter the
tyre is the less circular it is.

YOU and your ilk are claiming that this means that the thing that is
most important is the radius, even though a non circular object has no
constant radius.

What part of the concept of 'an effective radius' can't you get though
your thick left-brained head?

It DOES however have a circumference.

Given that there IS a peripheral distance (because under your rules
there isn't a true circumference either, it not being a circle or
ellipse and all) you *must* also have 'an effective circumference'.
That would be the distance a tyre *actually* travels per revolution.

That doesn't change.

That's the very thing it MUST do for any of the millions of iTPMS to
work!

So, the tread under the load point shrinks reducing the unloaded
(true) circumference to an effective circumference and the real
unloaded radius to an effective radius.

I bet you can understand i or j and how it represents the square root
of a minus number (something that is impossible in straight maths) but
you can't accept how a tyre can change it's effective circumference /
radius when it running at a lower pressure??

Bizarre.

Cheers, T i m