"I-zheet M'drurz" wrote in message ...
On 28 Oct 2003, Tony Hwang wrote:

Hi,
Which is power factor of 1(phase angle is aero). No loss circuit.
Pure resistive load which does not hardly exist in real world.
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
That's the key here. Thank you for saying it, prepare to
be belittled and badgered by those too simple minded to
understand.

Cos0(zer degrees) = 1.

Yes, be prepared to be belittled. Incandescent Lights are indeed near
perfect resistive loads and as far as I kow they do exist in the real
world.

Electric water heaters (and to a lesser degree dryers), near perfect
resistors, their job is to dissipate heat. Yes, if you are running an
air conditioner or fridge yes, there will be 10-15% reactive portion.
High crest factor current waveforms (in electronics) can also impact
usable power on a given breaker, but this is well beyond the scope of
the question. The question in this case will can ten 65 watt bulbs be
safe off a 15 amp circuit and the answer is yes, by more then factor
of 2.

Furthermore cos(phi) is an oversimplified for PF. Total power (real +
reactive) is the integral of the product of the voltage and current.
The current in many electronics devices being nonsinusoidal. Finally,
mathamatics is the TOOL quantify the PHYSICS in this problem. Circuit
breakers do not do math, they do follow the laws of PHYSICS. Now that
you have been belittled by someone simple minded perhaps you will not
post that which you are ill informed on.