On 12/30/2016 03:27 PM, trader_4 wrote:

[snip]

There better be or Kirchoff's Law would not work. Let's say
a 12V battery drives two identical light bulbs. Now let's
take a meter and follow the circuit starting with the positive
terminal of the battery. Place the positive meter lead on it,
the neg meter lead on the other side of the first bulb. You
get +6V. That is the voltage drop across the first bulb.
Now keep going. Take the positive meter lead and put it between
the two bulbs and put the neg lead on far side of the second bulb.
Again you get +6V, the voltage drop across the second bulb.
Now complete the loop by taking the positive
lead and place it on the far side of the last bulb and the neg
meter lead back where you started, at the beginning of the loop,
which is the battery positive terminal. You get a reading of -12V .
Add up the voltage drops around the loop:

6 + 6 -12 = 0

Kirchhoffs Law


Connect a third bulb in parallel with the second one above. The voltage
drops across the bulbs change, but the sum must remain 0.

In the same way, the sum of currents into a junction is 0. Still true
when the junction is in the middle of a 3-phase (wye) motor.

[snip]

--
Mark Lloyd
http://notstupid.us/

Losing your faith is a lot like losing your virginity you don't realise
how irritating it was 'til it's gone.