On Mon, 30 May 2016 21:28:19 -0400, FromTheRafters
wrote:

pretended :
On Mon, 30 May 2016 05:57:44 -0000 (UTC), Diesel
wrote:

notX Mon,
30 May 2016 03:19:44 GMT in alt.home.repair, wrote:

On 05/29/2016 09:23 PM, Diesel wrote:

[snip]

Just to clarify, the calculations I provided in this post aren't
FUD, unless you're able to dismiss the yellow Ugly electrician
reference book.

If it says you have voltage drop without load, it SHOULD be
dismissed.

http://www.uglys.net/

You have voltage drop due to the length and size of the wire. Because
the wire isn't a super conductor.

At the end of the day, you might have put 120 volts on the line, but,
100ft down that line, you aren't getting 120 volts. Some has been lost
on the wire, due to the wires own resistance.

Switch from AC to DC with no other changes, and the voltage drop is
more pronounced.
Absolutely totally 110% wrong.. There is NO voltage drop withouit
current flow.

You are WAY in over your head.

That's what *I* said, and you said I was wrong. Sheeesh, make up your
mind.
You appear to have said, I believe "You have voltage drop due to the
length and size of the wire. Because the wire isn't a super
conductor. "

You also appear to have said "At the end of the day, you might have
put 120 volts on the line, but, 100ft down that line, you aren't
getting 120 volts. Some has been lost on the wire, due to the wires
own resistance. "

And the context was an "open circuit."

Under a load, you are correct. On an open circuit, you are just plain
wrong.

If you did not say what you appear to have said, accept my apologies.