On Mon, 30 May 2016 19:55:22 -0400, FromTheRafters
wrote:

notX has brought this to us :
On 05/30/2016 04:28 PM, FromTheRafters wrote:

[snip]

Says you. Do you divide by zero for a living?

I seem to remember n/0 = INF (for nonzero values of n). 0/0 = NaN,

I'm not so sure about that last one, I've seen 0, 1, and infinity. All at the
same time. It's a fuzzy number. Very fuzzy.

You might be correct in that particular context.

https://en.wikipedia.org/wiki/Divisi...ter_arithmetic

If you are happy with the 'voltage drop' being somewhere between zero
and a very large integer (or infinity) then that's a plus for you.

Still, it can't really be a 'voltage drop' without energy being
dissipated by the device under consideration.
The voltage drop across the wire is ZERO. The total voltage impressed
acroos the circuit is the supply voltage. Since the voltage drop
across the conductors is zero, the voltage drop across the "open" is
supply voltage. (the voltage drop MUST equal the impressed voltage)
This is true with zero amps current flow. Because there is zero amps
current you can not solve for the resistance of the conductor because
(supply voltage assumed to be 12) 12/0 is indefineableand the
reistance of the open circuit is infinite (in a perfect world)