Thread: Wiring electric baseboard
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Diesel Diesel is offline
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Default Wiring electric baseboard

Mon, 30 May 2016 15:07:39 GMT in alt.home.repair, wrote:

On Mon, 30 May 2016 06:53:52 -0000 (UTC), Diesel
wrote:


Mon, 30 May 2016 06:09:42 GMT in alt.home.repair, wrote:

Voltage drop still depends on the load. If there is no load,
there is no voltage drop. If you have a wire with no load at
all, there will be full circuit voltage at both ends.

No, there won't. The wire isn't a super conductor. It takes a
little to push the electrons on it. The thinner and longer the
length, the more is lost in transit. If it were a super conductor,
what you've written would be absolutely true. As long as the wire
has resistance of it's own, we're subject to voltage drop. We have
various ways in which to minimize the voltage drop, though. Short
of using a super conductor however, we can't outright prevent it.


Bull****. If there is no current flowing, there is no voltage
drop.

Volts (dropped) = Amps x Resistance. If there are no Amps, it
doesn't matter what the resistance is, volts (dropped) is still
zero.

You might argue that when you actually measure the volts at the
far end, you are loading the circuit with your meter but a digital
meter has in impedance in the meg ohms so the current is still
virtually zero and you will still see the full voltage within the
accuracy of the meter.

You are correct. I wasted a significant amount of time by ignoring
the fact that the circuit wasn't completed yet. I will eat a large
amount of crow.

As a sanity check, notice voltage drop charts always base the
number on the load in amps times the resistance of the wire.

Yes, I've noticed.



--
MID:
Hmmm. I most certainly don't understand how I can access a copy of a
zip file but then not be able to unzip it so I can watch it. That
seems VERY clever!
http://al.howardknight.net/msgid.cgi?ID=145716711400
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