On Mon, 30 May 2016 16:50:22 -0400, FromTheRafters
wrote:

trader_4 explained on 5/30/2016 :
On Monday, May 30, 2016 at 4:19:08 PM UTC-4, Sam E wrote:
On 05/30/2016 06:13 AM, Al Gebra wrote:

[snip]

Voltage drop is represented by the formula E=I*R
Seems to me if the current flow is zero, then the voltage would be zero
as well.

IIRC, it's I squared R. Of course, it's still no voltage drop with no
current. Is it possible there's a confused poster here, who has R and
thinks it's E.

(I^2)R is the power drop. The voltage drop is IR

And no, it's not about a simple mistake, Diesel doesn't understand
Ohm's Law and electricity 101.

Power drop?

If there is such a thing in this context, which I doubt, it probably
requires current too.

Lost power in the circuit is a function of the voltage drop.

It is all moot in the case of the resistance heater in the example
that started this nonsense thread.
All of the power lost to voltage drop will still be returned to the
home in the form of heat and that was the object of the exercise in
the first place.