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FromTheRafters

It happens that formulated :
On Mon, 30 May 2016 10:37:01 -0400, FromTheRafters
wrote:

on 5/30/2016, Al Gebra supposed :
On 05/30/2016 12:53 AM, Diesel wrote:

Mon, 30 May 2016 06:09:42 GMT in alt.home.repair, wrote:

Voltage drop still depends on the load. If there is no load, there
is no voltage drop. If you have a wire with no load at all, there
will be full circuit voltage at both ends.
No, there won't. The wire isn't a super conductor. It takes a little
to push the electrons on it. The thinner and longer the length, the
more is lost in transit. If it were a super conductor, what you've
written would be absolutely true. As long as the wire has resistance
of it's own, we're subject to voltage drop. We have various ways in
which to minimize the voltage drop, though. Short of using a super
conductor however, we can't outright prevent it.

Voltage drop is represented by the formula E=I*R
Seems to me if the current flow is zero, then the voltage would be zero as
well.

That's a good theory, but IMO it is wrong.

Yeah that Ohm guy was a moron.

No, *he* knew quite well what he was talking about.

I suppose we should throw out the rest
of electrical engineering too as just a flawed theory.

Ah, engineering, no wonder the math skills are so weak. They use
calculus all day long but few of them know how or why it works.

Show me a definition of "voltage drop" that doesn't involve current
flowing in a circuit. I'll wait, but I haven't got forever so be quick
about it.