On Monday, May 30, 2016 at 1:57:48 AM UTC-4, Diesel wrote:
notX Mon,
30 May 2016 03:19:44 GMT in alt.home.repair, wrote:

On 05/29/2016 09:23 PM, Diesel wrote:

[snip]

Just to clarify, the calculations I provided in this post aren't
FUD, unless you're able to dismiss the yellow Ugly electrician
reference book.

If it says you have voltage drop without load, it SHOULD be
dismissed.

http://www.uglys.net/

You have voltage drop due to the length and size of the wire. Because
the wire isn't a super conductor.

At the end of the day, you might have put 120 volts on the line, but,
100ft down that line, you aren't getting 120 volts. Some has been lost
on the wire, due to the wires own resistance.

Heh, smart guy, give us your formula for that voltage drop in the wire.
The rest of us here, have told you that from a very simple application
of Ohm's Law, it's V = I*RW where I is the current flowing and RW is the
resistance of the wire. Set I to zero, what's the voltage drop? ZERO.
So, we can calculate it. Show us YOUR calculation.



Switch from AC to DC with no other changes, and the voltage drop is
more pronounced.


More FUD and diversion. The differences between switching from 240V AC
to DC in this discussion is totally negligible. Another example of an
amateur taking something they heard or saw and misapplying it.

PS: With DC, just like with AC, if the current is zero, the voltage drop
on the wires is zero.