In article ,
Vir Campestris wrote:
On 26/03/2016 14:53, Dave Plowman (News) wrote:
In article ,
Vir Campestris wrote:
Easy to remember. Two pies 'n' tea.

So:-
2 x pi x RPM x torque(lb.ft)
---------------------------- = BHP
33,000

Result is approx 112 bhp.


OK, now if it's generating 200BHP at 5000RPM, what's the torque? (I'd
have stuck with kW, about 84, with fewer conversions but that's not
important)

Think you may need to get your maths books out and revise. ;-)

Well, if it's too hard for you...

I'm not the one asking. And I've given you the means to calculate BHP or
torque at a given RPM. Which is why I suggested you revise your maths.

400nM at 2000RPM = 84kW (to the nearest integer) ~= 112HP.

Be better if you stuck to the same units.

Reverse the transformation, and from 200HP you get 210lb-ft, or 284nM. A
little over half. Right?

You are the one doing the calcs.

Now, if you have a gearbox attached to this engine, and you set it to
reduce the output shaft to 1000RPM, what is the resultant torque at
those two engine speeds?

What is the point of all this? A gearbox multiplies the torque in
relationship to the ratio of the gears, less any friction.

Andy

--
*Rehab is for quitters

Dave Plowman London SW
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