stuffing a refrigerator
On 7/26/14, 7:58 AM, Zaky Waky wrote:
J Burns wrote in :
I calculate that if you changed the air in an empty 17cu ft refrigerator
for air at 75 F with a dew point of 65 F, cooling it to 35 F with a dew
point of 0 F would mean moving 15 joules, or 1 watt for 15 seconds,or
1/240,000 kwh.
Check your calcs. They're wrong.
I was seeing if you were awake. Why don't you tell the class the correct
answer?
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