On Tue, 01 Jul 2014 16:57:13 -0400, Phil Hobbs
wrote:
On 07/01/2014 03:55 PM, Jim Thompson wrote:
On Tue, 01 Jul 2014 15:30:18 -0400, Phil Hobbs
wrote:
On 07/01/2014 02:56 PM, Jim Thompson wrote:
Nasty Math Problem of the Day...
http://www.analog-innovations.com/SED/MathNasty_2014_07_01.pdf
Any ideas?
...Jim Thompson
Move one of the arctans to the other side of the equation, take the
tangent of both sides using the formula for tan(a+b), and solve it
algebraically.
Cheers
Phil Hobbs
The arctans are on the one side.
As I see it, applying TAN to both sides gives
TAN(THETA) = TAN(arctan1 + arctan2)
...Jim Thompson
There are different ways to do it, but you'll need the tan(a+b) formula.
That'll make it an algebraic equation rather than a transcendental one.
Cheers
Phil Hobbs
A _messy_ Algebraic equation :-)
Oooops! I just realized the advantage of your approach... ding-dong
:-|
...Jim Thompson
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