On Tue, 21 May 2013 10:26:26 +0100, Martin Brown
wrote:
On 21/05/2013 09:11, Jasen Betts wrote:
On 2013-05-20, Martin Brown wrote:
On 20/05/2013 10:49, Jasen Betts wrote:
On 2013-05-20, Martin Brown wrote:
On 19/05/2013 22:09, Tom Del Rosso wrote:
The algebraic solution is in the form
A = F(a,b)
B = G(a,b)
Where A,B,a,b are all integers with some of them non-zero.
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
In the general case they are all non-zero.
Your task is to find the functions F(), G().
functions?
F(a,b) = sqrt(a^2+b^2)
G=F
that seems way too easy
sqrt(a^2+b^2) isn't an integer except in a handful of special cases.
hey! stop changing the rules!
I didn't change the rules. Though I left the question open at first.
Martin Brown wrote:
given a^2 + b^2 = c^2 where a,b,c are integers
I am actually not going to post the answer here and would ask that
anyone who does work it out do likewise. It is obvious once you see it.
[snip]
But it falls into my category of "trick" questions. I finally figured
it out, but I frown on using such gimmicky problems with students.
...Jim Thompson
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