On Jan 14, 2:17*pm, "
wrote:
On Jan 14, 3:37*am, harry wrote:









On Jan 13, 10:18*pm, "MarkK" wrote:

Ill repeat my reply here for the sake of those that filter google groups

thats actually a *real interesting question...

with a pure reactive (inductive or capacitive) load, the current flow
in the windings will cause a voltage drop but if i'm not mistaken
since there is no (or very little) actual power flow, there will not
be a load on the engine so the engine speed will not be a factor.

with a pure resistive load, the current through the windings will
cause a voltage drop AND there will be a load on the engine that will
try to slow it down. *It is the job of the speed governor on the
engine to keep the speed constant. *If the speed drops the voltage and
frequency will drop due to the engine speed drop.

So for a given amps, you may get more of a drop with a resistive load
depending on how tight the governor speed control the engine.

Mark

You neglect the resistance of the generator windings.-

I don't see that he neglected the resistance of the
generator windings. *In a generator the resistance of
the windings is very small, negligible compared to
the resistance of any real load.

If there is no resistance in the load (ie purely inductive/
capacitive), it would be the only resistance in the circuit and hence
hugely important.

There is no such thing as a pure inductor BTW.
There are almost pure capacitors.