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Ignoramus27678 Ignoramus27678 is offline
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Default Very OT - probability paradox

On 2011-11-06, Bob Engelhardt wrote:
Given: an opaque jar with a large number of white & black marbles, same
number of each. If I pick 2 marbles randomly, it seems that the
probabilities depend upon how I do the drawing.

If I pick one marble, then pick another, the probability of drawing one
black and one white marble is 50%. (4 possibilities, 2 of which give 1
white & 1 black.)

If I reach in and pick 2 marbles AT ONCE, the probability is 33%. (3
possibilities, 1 of which gives 1 of each color.)


3 possibilities, unequal probabilities.

Your reasoning is wrong.

i


It just doesn't SEEM right that the probabilities could be different.
Why is it different? Or is it not different? Is there really 4
possibilities when drawing 2-at-once?

Drawing 3 marbles gives even worse results. One-at-a-time gives:
1/8 probability of all black,
1/8 all white,
3/8 2 black + 1 white, &
3/8 2 white + 1 black.

3 at once gives:
1/4 all black,
1/4 all white,
1/4 2 black + 1 white, &
1/4 2 white + 1 black.
The probability of drawing all same color 3-at-once is twice that of
one-at-a-time!

Is there a statistician in the house?

Bob