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How much force does a common shop vise develop in its jaws? Google was
pretty unhelpful on this - the only reference I could find suggested
up to 7000 lb. Another paper suggested that a minimum required
clamping force for machining is much less - up to 1000 N.

I am interested because I am trying to guess how much force I can
develop in this press:

http://www.flickr.com/photos/2768312...57622484352534

Right now my answer would be "not enough" (see the following photos if
you are interested in the process).

Can anybody suggest how such force could be measured?

Michael Koblic,
Campbell River, BC


The formula to find the force exerted by your screw is
F= 2*Pi*r*p*f

F is the force of the screw
Pi is 3.14159
r is the distance from the center to the handle
p is the screw pitch
f is the force you exert on the handle

from the photo, I estimate the screw multiplies your force by a factor of
75.

However, evenly applied force is not the way to remove bubbles. You will
just trap them and compress them. The way to remove bubbles would be to
run the plate and film between two rubber rollers with a rigidly-held, but
adjustable gap. Another way is to apply the force through a slightly domed
rubber pad so the center contacts first and the air is pushed to the
outside. You have to make sure the rubber is compressible enough and the
force is great enough that you make contact on the outer edge.