On Apr 15, 10:47*am, Home Guy wrote:
" wrote:
Take a look at the dual voltage source circuit diagram that Jim
Wilkins supplied a couple posts back. *It's example #1.

http://www.electronics-tutorials.ws/...its/dcp_4.html

I did, you dumbass #2.

Go and read my last post.

I have read your posts and like most other people here
have concluded you are wrong, so I don't see why
you're calling ME the dumbass.



It's a simple diagram of two ideal voltage sources with
series resistors connected to a load.

And note what happens when the voltage sources have unequal voltages.

Uh, huh. I have noted that and if you have any questions about how
that works, I'll be happy to answer them. I'm still waiting for your
answer about the case with EQUAL voltages. That was the essence
of your argument, was it not? That a power source can't provide
power in parallel with another unless it raised the voltage? So,
leave everything else the same and just make the voltage sources
equal. Tell us what current flows through the load resistor and what
currents flow through each voltage source. This is EE course circuit
theory course 101, about the first week.

BTW, you have an engineering degree?



And note that we are not talking about batteries here in the case of a
municipal power grid and a PV system.

Yes and since you seem incapable of understanding a simple
circuit that represents 2 batteries connected in parallel to a
load, no need to add the additional complexities.



And I'll bet if you do the equations with the voltage sources
at the same value, you'll find that twice as much current
flows from the voltage source with the 10 ohm resistor as
the one with the 20 ohm resistor.

If that diagram shows reverse current flow because Battery 1 has a lower
voltage than Battery 2 (and current I1 is negative), then at what point
does current I1 become zero? *What would the voltage of battery 1 have
to be for current I1 to be zero?

I see you do have a question.
Simple. With no current flow through battery 1, then the circuit
is reduced to an ideal voltage source connected to two resistors
in series. One of these represents the internal resistance of
battery 2 and is 20 ohms. The other is the load resistor of 40
ohms. So, we have 20 volts across 60 ohms, giving a
current of .333Amps. That .333amps produces a voltage of
13.34 across the load resistor. (.333 A X 40ohms.) That means
voltage source V1 would have to be at the same potential,
13.34 volts and when it is, no current flows through what
represents battery 1.

I've answered your question, now answer mine:

What are currents I1, I2, I3 when the voltage sources V1 and V2
are both 20 volts.