On Apr 13, 1:05*am, Jim Wilkins wrote:
On Apr 12, 7:50*pm, Home Guy wrote:

...
Hypothetically speaking, let's assume the local grid load is just a
bunch of incandecent lights. *A typical residential PV system might be,
say, 5 kw. *At 120 volts, that's about 42 amps. *How are you going to
push out 42 amps out to the grid? *You're not going to do it by matching
the grid voltage. *You have to raise the grid voltage (at least as
measured at your service connection) by lets say 1 volt. *So all those
incandescent bulbs being powered by the local grid will now see 121
volts instead of 120 volts. *They're going to burn a little brighter -
they're going to use all of the current that the local grid was already
supplying to them, plus they're going to use your current as well.
...

Bad analogy. The 1V will be lost in the internal resistance of the
inverter connection, which is much higher than that of the grid. Think
of pouring water from a bucket into a lake. There's NO measurable rise
in the lake level.

jsw

What happens to the "say" 1volt. It is only a local thing because
the utility drops it's output by 5Kw. Sure, there will be different
current flow around the system but nothing that can't be handled.

I don't know why you rabbit claiming it doesn't work when it clearly
does.