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Pete C.

wrote:

On Sun, 16 Jan 2011 11:30:21 -0500, "RBM" wrote:

I'm trying to determine the force in tons of a hydraulic cylinder. Being
mathematically challenged, even having a formula would be like reading
Chinese to me.
The cylinder has an outer diameter of 3.5", the shaft is 2", as best I can
figure from information derived from the net, the bore would be 3". It has a
stroke of 18". It will be fed from a pump delivering 8 GPM @ 2100 PSI.

Any help would be appreciated

You have the force answer, if your pump really puts out 8 GPM at 2100
PSI it will fill that cylinder in around 2 seconds.

What this means is that the splitter should function well with the skid
steer at or near idle speed.