On Jan 8, 6:37*pm, Harry K wrote:
On Jan 8, 6:47*am, harry wrote:
On Jan 7, 4:56*pm, Harry K wrote:
On Jan 7, 12:30*am, harry wrote:
On Jan 6, 4:47*pm, Harry K wrote:
On Jan 6, 12:57*am, harry wrote:
On Jan 5, 4:32*pm, Harry K wrote:
On Jan 5, 12:17*am, harry wrote:
On Jan 5, 4:52*am, Harry K wrote:
On Jan 4, 8:17*pm, Robert Neville wrote:
DerbyDad03 wrote:
Is there really no noticeable difference between 40 PSI and 60 PSI?
There is for me. We're on a well with a storage tank located about 250' away and
100' below the house grade. A 5 stage booster pump set to output 65 psi at the
tank level results in about 40 psi at the entrance to the first floor of the
house, less after distribution throughout the first floor and even less on the
second floor.
Would love to have 60psi at the house entrance, but that would involve replacing
the booster pump with a very expensive 8 stage booster pump or installing a
second booster at the house.
Something does not compute. *Psi of 65 should only be 22 psi at 100'
rise...some less than that after the loss through 250' of pipe.
Harry K
0.4336 psi in a foot head as I remember. We are on "bars" now in
Europe.
Frictional pipe losses depend on flow on any particular system.
No flow=no loss.- Hide quoted text -
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And no flow=no water being used so your point is? *Static pressure is
pretty immaterial in a water system.
Harry K- Hide quoted text -
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Static pressure is that due to the hieght of the reservoir above your
house. It runs the whole system. *Pressure drop is due to the
frictional losses in the pipework due to water flowing through it.
The point is that a restrictor creates a pressure drop that depends on
the volume of water going through it.
It is an additional frictional loss, not a pressure reducer per se.- Hide quoted text -
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??? Do you have a point that is unknown to everyone already? *To make
it clear. *I know what a PRV vavle is and what it does.
BTW the PRV does reduce pressure even at static. *Case in point was my
town down in a canyon. *They built a new reservoir up on the rim.
Blew fittings all over town _even when no water was being used_. *Also
my mothers house when I installed the PRV there. *Reduced pressure to
55 psi _static_.
I repeat - static pressure is pretty meaningless *in the operation of
a water system. *It is what it does _dynamically_ that counts.
My original system here was from a commuity well over a 1/4 mile
away. *Static (30/50) *was just fine, dynamic wouldn't run an impulse
sprinkler.
Harry K- Hide quoted text -
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I think you need to go an read a few books. You are in cloud cuckoo
land and in need of education.
If your system was from a well, there would be
*(a) Elevated storage tanks filled by pumps down/adjacent to the
wells. Giving static pressure. I assume water runs downhill even in
America. Or maybe you don't know this.
Or
(b) A pumped pressure system. Less likely as no electricity instantly
means no water..- Hide quoted text -
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BTW no power on a pumped system does _not_ mean mean instantly no
water. *I suggest you discover what the pressure tank is for.
Harry K- Hide quoted text -
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The pressure tank stops the pump from "hunting". It is in fact a
reservoir,
It is in fact the reason for this question. *It is the cheap
alternative to the elevated reservoir
The pump starts when the pressure falls to (say) 40psi. And it stops
when the pressure rises to (say) 60 psi.
The alternative would be to have the pump constantly running. If no
water was flowing, this would lead to the water heating up, cavitation
and damage to the pump. Not to mention increased electricity costs.
Like many Yanks, I can see you have no concept of theory/science.
If I have a water system fed from a tank at the top of a hill 100'
high, the static pressure would be 43.36psi.
No ****? *Odd, that figure has been known for hundreds of years or
more. *Did you just find it out?
If I wanted any more pressure. I could add a pump. The pressure added
by the pump would be dynamic pressure.
Well, no **** Dick Tracy. *The Russians have a saying for such "Look,
he just discovered America" which is about a sarcastic as it can get.
If water was to be taken from the system, the pressure would fall due
to frictional losses in the pipework. Also measured in psi (or feet
head or bars,)
All this can be calculated out.
Which I pointed out in my first post. *Which you somehow either missed
or decided to argue about.
I can't make it any simpler than that for you. If you still can't
understand, you'll have to continue in your ignorance.- Hide quoted text -
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Since you just repeated what I have been saying since the beginning of
this idiotic diversion... *Did I perhaps educate you to the point you
can regurgitate it? *My whole point in this is that you keep saying
things that everyone already knows and adding zilch to the thread.
If there is any misunderstanding it is on your part. My posts were
clear to anyone older than 9.
I see you didn't address your error in saying that no electricity
results in instant no water.
Now if you can go back through the thread and quote _anything_ that
shows I don't understand what I am talking about feel free. *I won't
hold my breath.
Harry K- Hide quoted text -
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"Simple. Pump fills pressure tank no matter where it is. Pump shuts
off at cut-off pressure. That is the STATIC pressure. Open valve
and water flows with DYNAMIC pressure dropping. It does that whether
it is a pumped sytem or feeding from a reservoir. What the DYNAMIC
pressure is determines hwo well the system works".
It is not the static pressure. The pump is stopped or static, but
that's something else.
http://en.wikipedia.org/wiki/Fluid_s...tatic_pressure