"effinperfectionist" wrote in message
. com...
Al Reid wrote:
"Still wrong since you are not taking efficiency and power factor in to
account and you are using a ficticious voltage."

No, I'm not wrong. I said IF it could actually DRAW 21A at the peak
voltage
of 155V, then the math gives you power consupmtion of 4.4HP. Efficiency
is
not relevant, as I'm talking purely about consumed power (input power).
Thus, if a 21A peak coincides with a 155V peak, the power consumption at
that moment is 4.4HP. I am NOT talking about power delivered to the
cutting
teeth, or wherever else you may choose to measure it, I'm talking about
the
total consumed power of the machine.

And, 155V is not ficticious.......it's the peak instantaneous voltage for
a
110V sine wave.
(110VACrms / 0.707)


It is still meaningless. It is not a DC machine. It is still rated based on
the RMS input voltage. Mow if you wnnt to apply a higher (155VRMS) input
voltage, then you would be correct.

The only measure that has any value is the HP and torque at the output
shaft. I don't care how many amps go in, I want to know how much HP is
developed.

To quote myself:

" Now, if it can DRAW 21A at Vpeak (155V) without turning in to a puddle,
then
it can CONSUME POWER EQUIVALENT to 4.4HP, though it still wouldn't be
cutting wood at that rating."