Hi,

Yesterday, for the first time I saw what was inside a baseboard
radiation: 3/4" copper tube with fins. I see how the fins can be
efficient at releasing the heat. But the volume of water is minuscule.
Over an 8' run, the amount of water in the tubing is

pi*(3/8)^2*8*12*0.0173160173 = 0.734398282 quarts

But how much heat can be contained in less than a quart of water?

Many thank in advance!

Sam