On Mon, 09 Aug 2010 16:37:19 -0500, John Fields
wrote:

From the schematic:

1. Set the DSO for a single sweep triggered by channel 1 going high.

2. Pull M1 away from M2 and M3, which are just barely touching,
and let them settle for a few seconds.

3. Arm the DSO.

4. Release M1 so that it hits M2 directly across from where M3 is
touching M2.

5. Read the time it took for channel 2 to go low after channel 1 went
high. That'll be the time it took for the momentum accumulated by
M1 to be transferred to M3.

---
"Slow", "Medium", and "Fast" refer to the pulse width of the pulse on
channel 1, the width of which was determined by releasing the ball
farther and farther from plumb.

the fact that there _is_ a trailing edge means that M2 wasn't hit
squarely or that there are imperfections in the rig.

In either case, the bounce represents an impedance mismatch reflecting
power back from the load to the source.

In any case, the momentum transfer time is from the leading edge of
the trace on channel 1 to the falling edge of the trace on channel 2.

I'll get some more data together as time permits, and post it, and the
video's in the works...

---
JF