On Sat, 06 Feb 2010 10:46:43 -0500, Joseph Gwinn wrote:

In article ,
Wes wrote:

Joseph Gwinn wrote:

The force you need will be the area you're cutting through multiplied by
the
shear strength, plus a bit for luck.

Area, or is it perimeter?

Area I think. Which would be permimeter x material depth x shear

Area of the sheared material, but not of the piece being punched out.
That's the distinction I was making.

Joe Gwinn


Yes, I guess I skipped that part of the explanation. My bad.


Mark Rand
RTFM