Joseph Gwinn wrote:

The force you need will be the area you're cutting through multiplied by the
shear strength, plus a bit for luck.

Area, or is it perimeter?

Area I think. Which would be permimeter x material depth x shear

Wes
--
"Additionally as a security officer, I carry a gun to protect
government officials but my life isn't worth protecting at home
in their eyes." Dick Anthony Heller