Dave wrote:
On 1/8/2010 7:28 AM Dave wrote:
The formula I found for total ohms in a series circuit is to add up
all ohms in the circuit. For parallel circuits its 1/RT = 1/R1 + 1/R2
so 1/2.8398 + 1/5.6534 = 8.5472/16.35980892 which is something like
5.2245 ohms. The total for a combo circuit is to add the parallel
value to the series values and I come up with a total of 19.9873.
Nothing even close to your 4.1433. So I'm clearly not understanding
how resistance math is supposed to work.

Ok, I screwed my math up on the parallel circuit. Here's my revised math:
1 / (1/2.8398 (0.35213) + 1/5.6534 (0.17688) = .52901) = 1.89032 ohms.

So add this to the remaining values stated:

1.89032 + 7.0134 + 7.7494 = 16.65312

Still no where near your 4.1433.

What am I doing wrong?

1.89032 + 7.0134 + 7.7494 = 16.65312

The 7.7494 is in parallel with the rest.