On Thu, 8 Oct 2009 09:18:59 -0700, DaveC wrote:

peak = RMS * sqrt(2) = 110 * 1.414 ~ 155V

JF

This is for half-wave rect.?

Thanks.

Half-wave and full-wave rectification result in the same peak voltage.
It's just that for full-wave, the peaks occur twice as often.