Wiring Double GFCI?
"Doug Miller" wrote in message
...
In article
, Sev
wrote:
On Sep 19, 8:34=A0pm, (Doug Miller) wrote:
In article
.=
com, Sev wrote:
On Sep 19, 1:55=3DA0pm, stan wrote:
3) If the intention is to feed two live leads form a double pole
breaker, with one live wire to each GFCI; it won't IMO work because
there will automatically be unbalance in the common neutral; the
moment something is plugged into the 'other' GFCI circuit.
This is incorrect, isn't it? Comments?
It's unclear *which* you believe is incorrect, the wiring method, or the
description of why it won't work.
Answer: both. The wiring method is indeed incorrect. The description of
why it
won't work is also incorrect, but needs only the addition of three words
at
the end -- "and powered on" -- to make it correct.
Really? With opposite phases (implied by "double pole breaker") I
thought this was ok.
Yes, really, for exactly the reason stated: as soon as anything is powered
on,
on either leg of the circuit, current flows in the neutral wire. The GFCI
on
the *other* leg of the circuit sees that the current in the neutral wire
is
not the same as the current in *its* hot wire, and trips.
If you want GFCI protection on the outlets of a multiwire circuit, there
are
only two ways to do it: with a double-pole GFCI breaker, or with a GFCI
receptacle at *every* location you wish protected, wired to the LINE side
only.
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