On Sat, 12 Sep 2009 09:05:27 -0700, life imitates life
wrote:

On Sat, 12 Sep 2009 09:53:47 +0100, Pomegranate *******
wrote:

The relay will drop out only when the coil current falls below the
hold-in current. Any suppression method allows the coil current to
gradually decay to zero and must lengthen the drop-out time.


Wrong. You're an idiot. A diode does NOTHING to reduce current via some
gradual decay, you dumb****.

It is a surge device, It eats the entire current, at its maximum rate.

That is not decay, you stupid ****.

The relay coil would drop out immediately by your retarded definition
because the current is removed instantly in most wave forms from the
drivers. The diode clamps the collapsing field's spike. That spike has
no energy to provide the coil with anything that keeps the latch plate on
it.

So you not only know nothing about the "inductive circuit", you also
know nothing about the mechanical operation of the relay assembly either.

Your wrongness is becoming a work of art. Nobody could be this
consistently wrong by mere chance.

The Fujitsu small telecom-type relays that we use have about a 3:1
dropout time ratio, as measured at the contacts, for diode clamped
versus unclamped coil drive respectively.

Try it on some real relays yourself.

John