Martin wrote:
"Stuart Noble" wrote in message om...
if KWh is above 670 then C23-670 multipy
by C29, but if below 670, then answer should be 0 (zero)

Google for "open office if statements".

It's probably

=IF(c31670;(c23-670)*c29;0)

if I've got the cell numbers right. There's probably a more elegant way ....

Not sure if it's any more elegant, but having used MIN for the first 670, the_constructor could use =MAX(0;(c23-670)*c29). And I don't see any advantage in not combining the two elements in one cell, per my original post.



I think you are right and I have, to a certain extent, programmed
spreadsheets professionally.

Max and Min are not so much "more elegant" but I would say "more easily
understandable".

Hope that makes you feel better ;o)