"Stuart Noble" wrote in message om...

if KWh is above 670 then C23-670 multipy
by C29, but if below 670, then answer should be 0 (zero)


Google for "open office if statements".

It's probably

=IF(c31670;(c23-670)*c29;0)

if I've got the cell numbers right. There's probably a more elegant way ....

Not sure if it's any more elegant, but having used MIN for the first 670, the_constructor could use =MAX(0;(c23-670)*c29). And I don't see any advantage in not combining the two elements in one cell, per my original post.


--
Martin