"the_constructor" wrote in message o.uk...

"Steve Lupton" backwards.moc.liamg@pulevets wrote in message
...
the_constructor wrote:
Got a little problem trying to sort out a formula for a spreadsheet. Yes,
some of you may think that I should use a different group, but all the
computer groups are not as helpful as this group.

If (C23670) Then Let C31 = (C23*C27)


Hi

You don't say what to do if C23 is not less than 670. Assuming '0' for
now:-


=IIF(c23670,c23*c27,0)


IIF works like this:-

iif(something is true, put this value, otherwise put this value)


Steve
C32 is the cell which deals with KWh above 670, thus:

=(c23-670)*c29

Providing C23 = 670 .... ;-)


--
Martin