"The Phantom" wrote in message
...
The imaginary part of the impedance of this circuit:
...
is never zero.

Ya- so I'll have to differentiate, which means squaring the denominator too.
Plenty to loathe, but at least it equals zero so I don't need the stinkin'
denominator. I guess that w^5 term will become the quartic, but y'know,
there's only w^3 and w^1 imaginary terms, which are pretty easy to factor.
Think I'll go do some scratching...

Tim

--
Deep Friar: a very philosophical monk.
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