John Larkin wrote:
On Sat, 17 May 2008 22:39:43 -0700, "RST Engineering \(jw\)"
wrote:

The top dielectric layer is 12 mils, so a 50 ohm trace is only 20 mils
wide.
My calculator says 22 mils at one Gig, and not knowing your frequency of
operation puts me at somewhat of a disadvantage. I wonder if the mismatch
between 20 and 22 is honking things up.

It's wideband, DC to maybe 2.5 GHz, corresponding to roughly 150 ps
edges. I don't want something as simple as the pcb degrading what the
circuit can do, hence the desire to keep the traces very short. That
beats spending $1000 or so on better boards. Things are not yet honked
up; the board hasn't even been built.


Check with your fab houses whether they can do partial-Rogers boards.
Might be the ticket here.

[...]

--
Regards, Joerg

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