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terry terry is offline
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Default 8-gauge low voltage wire

On May 4, 3:42*am, " wrote:
Actually the new location of the transformer would be roughly in the
middle of the string. My plan is to run 8 gauge wires to the where the
middle of the string is, and connect it up to the existing 12 gauge
string.


If lights are "pretty dim now" are they 'all' dim or are the ones
nearest the transformer brighter?

Does the transformer get quite hot? If so it may be incapable of
putting out enough power; so can you reduce the number of lights by
say 10 or 20 per cent?

If feeding from one end now feeding instead from middle might make a
difference; because there should be approx. half the voltage drop in
the wires.

New 8 gauge wires from transformer to the middle should 'help' but
without detailed info hard to calculate.

#12 AWG will drop voltage by volts, per 10 feet for each amp of
current flowing.
#8 AWG will drop by volts, per 10 feet, for each amp of current.

If, for example the lamps themselves are 12 volts; take the total
wattage of all the lamps and divide it by 12; the answer will be the
number of amps flowing from the transformer.

For example suppose there are ten lamps each of 20 watts; 10 x 20 =
200 watts.
200 watts divided by 12 = 17 amps.

Each ten feet of #8 wire (2 conductors) will, at 17 amps drop voltage
by approx. one quarter of a volt. (0.228v)
With #12, about six tenths of a volt. (0.56v)

Doesn't sound like very significant?

Just how many lights of what total wattage are on that low voltage
system?