On Mon, 7 Apr 2008 04:17:32 -0700, "William Sommerwerck"
wrote:

"Jeff Liebermann" wrote in message
.. .

While you're fabricating another worthless response, you might
consider that the same mechanism that inspires metals to emit x-rays
is what causes phosphors to emit light when pounded on by electrons.
When the electrons in the inner orbits are knocked out (ionized) by
the bombarding the electrons, the outer electrons fall into these
inner orbits to replace them. The distance traveled between the outer
and inner orbits is the wavelength of the radiation produced.

Uh huh. Yeah.
Please review your quantum physics.

I'm not much of a fizzixist. Where did I go wrong? Digging...

According to my understanding of the Neils Bohr model of the atom, the
emitted wavelength is:
Wavelength =
1240 Electron-Volt-NanoMeters / (Energy difference between orbits)
http://www.mhhe.com/physsci/astronomy/applets/Bohr/content_files/section2.html

Oops. I'm wrong. The wavelength is not the distance travelled. It's
proportional to the difference in orbital energy levels, not the
distance travelled.

The difference between the binding energies of the inner and outer
shell electrons is the energy of the radiation produced.

That's much closer to correct.

Unless there are some losses involved that I don't know about, the
energy of the emitted radiation is exactly the difference between
orbital energies.


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