Franc Zabkar wrote:

On Wed, 19 Mar 2008 20:57:29 +0000, Baron
put finger to keyboard and
composed:

Another thing I noticed was
that the output capacitors, there is two in series for each lamp, seem
to be very small values. They are marked 18J 3Kv. I assume that is
18pf 5% 3000 volts working.

An 18pF capacitor would have an impedance at 100kHz of ...

1/(2.pi.f.C)

= 1/(2 x 3 x 10^5 x 18 x 10^-12)

= 1/(108 x 10^-7)

= 100Kohm

If 100Kohm were in series with the lamp, then the lamp would be
drawing a miniscule amount of current.

- Franc Zabkar

Thanks Franc,
I followed your maths perfectly.

--
Best Regards:
Baron.