Smarty wrote:

In an earlier reply I did indeed make a mistake, and erroneously typed a
percent sign % when I intended to type a notation for degrees °.

Let's not forget your 100x6.39/0.09 = 7100% computational error :-)

For 70% indoor temp and 30% indoor humidity, you avoid evaporating about
.09 gallons of water per day...

Smarty measures temperatures as percentages? :-) On my planet, 70 F air
at 30% RH has a humidity ratio wi = 0.0047 pounds of water per pound of
dry air, so keeping a 224 cfm house 70 F at 30% with an outdoor humidity
ratio wo = 0.0025 requires evaporating 224x60x0.075(wi-wo) = 2.22 pounds
of water per hour or 53.2 pounds of water per day, ie 6.39 gallons.

Nick