poster3814,

Your reply to the numerous comments from me and others never indicated any
opinions or conclusions on your part as to which of the humidistat
approaches you prefer. As I imagine you are aware, both the Aprilaire and
the Honeywell humidifiers can be used with other humidistats, and in fact
the Aprilaire humidifier could be used with the Honeywell humidistat or vice
versa. I bring this up because you may not be aware of this based on your
more recent thread, once again comparing Aprilaire to Honeywell.

In an earlier reply I did indeed make a mistake, and erroneously typed a
percent sign % when I intended to type a notation for degrees °. I think it
was still apparent that my references to temperature and humidity of 70 and
30 respectively were pretty obvious despite the typo. Sorry for the wrong
keystroke.

Smarty



"poster3814" wrote in message
ink.net...
wrote:
Smarty wrote:

Since you think I am, to use your word, "bluffing", I will answer...
An order of magnitude drop in water / evaporation energy consumption
occurs when a corresponding order of magnitude drop in air leak takes
place (from 224 to 24)...

Wrong problem :-) I asked:

If your average US house naturally leaked 224 cfm on an average 30.4 F
Philadelphia January day with an outdoor humidity ratio wo = 0.0025,
how would the fuel consumption change if you

a) airsealed it to reduce the natural air leakage to 24 cfm, or

b) humidified it to 50%, with no airsealing?

but Smarty talks about airsealing WITH humidification, which isn't
needed,
given enough airsealing and natural indoor humidity sources like people
and green plants, but let's solve the problems he poses...

For 70% indoor temp and 30% indoor humidity, you avoid evaporating about
.09 gallons of water per day with the correspondingly tiny drop in
energy
consumption.

Smarty measures temperatures as percentages? :-) On my planet, 70 F air
at 30% RH has a humidity ratio wi = 0.0047 pounds of water per pound of
dry air, so keeping a 224 cfm house 70 F at 30% with an outdoor humidity
ratio wo = 0.0025 requires evaporating 224x60x0.075(wi-wo) = 2.22 pounds
of water per hour or 53.2 pounds of water per day, ie 6.39 gallons.

A 24 cfm house requires 0.68 gallons per day, and the difference is
5.71 gallons, at an energy cost of 47.5K Btu/day, about 0.5 therms,
or $1/day at $2/therm.

Conversely, if you wanted to raise it to 50% humidity inside, you need
more water / energy, the amount of which is again determined by what
initial indoor temperature and humidity you specify... I used 70% and
30% once
again, and, on this basis, see an ncrease of .15 gals of water to be
evaporated per day...

So Smarty is perfectly capable of providing different wrong answers
for the same 70F/30% problem :-)

... Enough of your nonsense!

*****Plonk*****

When a man is wrong and he won't admit it, he always becomes angry :-)
Nick


Thanks again for the replies. For what it's worth, I'm going to start a
new message thread that is somewhat related but not totally related.
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