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James Sweet James Sweet is offline
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Default LCD LED backlight question

stoneattic wrote:
James T. White wrote:

"stoneattic" wrote in message
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See page 11 of the spec sheet. VF(typ) = 4.1V @ IF = 112ma.

So you will need a series resistor sized to drop .9V at 112ma.

--
James T. White




Thanks! That's actually what I thought but I wasn't sure I was reading
that correctly on the spec sheet. So an 8 ohm resistor is the way to
go? I assume a 1/4w would be fine?

Thanks again



In a pinch you can start with a 500 ohm or so pot, then set it to max
resistance, measure the current with a DMM and adjust the pot to get the
desired current/brightness and then disconnect the pot, measure the
resistance of that and choose a fixed resistor as close as you can get.
1/4W should be plenty, 1/8W should work too.