DIYbanter - View Single Post

wrote:
The current in theory to
open the resistor would have to exceed 3.24 amps.

How did you calculate that? P=I^2R -- I=sqrt(P/R) --
sqrt(7W/1.5ohm)=2.16A

So I was thinking
perhaps a 4 amp fuse would do.

2 amps, rather :-) and I wouldn't use one with any higher rated current
than "the original one (the resistor)" had...

Anyone have any thoughts on this?

It depends on that did the resistance of the resistor have any purpose,
or was it just to heat it up so that it will work as a fuse. That is of
course highly possible in case of such low resistance...if you can tell
it, your idea might work, although it sounds a little crazy :-)