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Default Geometry help needed

On Mon, 10 Apr 2006 23:58:00 GMT, "CW" wrote:

Nope.

"PDQ" wrote in message
.. .
Give all this balderdash, were one to lay out a horizontal base line of 2"
and erect a vertical line at one end of the base line that is 1" in height,
the distance between the two unattached line ends would be exactly sqrt 3"
long.


NO. The line joining those ends is the hypotenuse. Never mind the
other relationships, but consider that the hypotenuse is *always* the
longest side of a right triangle [very simple to prove]. Drag out
your calculator if you have to, but sqrt(3) is about 1.7321, which is
still less than 2 where I come from.

In your diagram the length would be sqrt(1^2 + 2^2) = sqrt(5), and the
angles would not be 30,60.