Geometry help needed
On Mon, 10 Apr 2006 03:16:56 GMT, "Gooey TARBALLS"
wrote:
Perhaps you would care to post your solution here?
In ASCII ? Not really !
My searching seemed to indicate it was a Trig problem.
You can do it either way. For a general solution to any angle, then trig
would be the way to go - especially with cheap calculators. However
90°. 60° and 30° are easy constructions with just dividers and they're
worth knowing.
Draw a circle. With your dividers set on the same radius, step out this
distance repeatedly around the circumference of the circle. It fits
exactly 6 times, meaning that the radii to each of these points make
angles of 60°.
To get from 60° to 30°, then you can either bisect it or you can
subtract 60° from 90° (you'll often already have a right angle laid out
for some other purpose).
To bisect the angle, use the dividers as before and mark out a point at
approximately two radii from the centre, at the intersection of arcs
drawn from two of the circumferential points you marked earlier. A
radius drawn out to this point bisects the circumferential points, at an
angle of 30°
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