In article , Ned Simmons
says...

.62 in^2 x 20000 lb/in^2 = 12400 lb.

Which is pretty close to the yield of the full (unthreaded)
wall of the pipe.

Again, the trouble arises with the sharp V form
at the root of the thread, and also the die-cut
threads. Those are the two *worst* situations
to have when one is trying to optimize the
strength of the joint.

Each of those will substantially reduce the
load carrying ability of a connection like that.

A proper fastener will have a) rolled threads,
with b) a bit of a radius or flat at the root.

Jim

==================================================
please reply to:
JRR(zero) at yktvmv (dot) vnet (dot) ibm (dot) com
==================================================