On Wed, 15 Feb 2006 15:27:22 +0000 (UTC), the renowned
(Ken Smith) wrote:

In article ,
Spehro Pefhany wrote:
[....]
Using mpg fuel consumption:

miles per hour = ((income in $/hr) * mpg)/($ per gallon)


Since the fuel use rises as the square of speed, in the range we are
talking about, we can use the MPG at 60 and write:

Y = (I * MPG60)/((Y/60)^2 * P)

if I did my math right:

Y = cubert( I * 3600 * M / P)

whe

Y = speed in MPH
I = income in $/hr
M = MPG at 60
P = price in $/gal

Tryin with some easy values:

Y = cubert(100 * 3600 * 30 / 3) = cubert(3.6E3) =150+a little

Yes, that sounds reasonable enough.

OTOH, if you want to make it 55mph, you have to assume someone working
at Walmart wages and driving a poorly tuned 72 Caddy or something like
that. Gas is still way too cheap for it to be worth conserving from an
economics pov.


Best regards,
Spehro Pefhany
--
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