On 13 Feb 2006 08:06:03 -0800, "motor man" wrote:

A bear managed to bend a steel door to a food locker in Yosemite. The
door is hinged on one side and pinned on one corner ( the camper forgot
to close it properly!!) , so the bend is across the diagonal. I
wondered how much force the bear had to use to bend it. The doors are
about 24" square and about .1" thick.
Anyone have any ideas? My calculations based on sheet metal bending
formula come out to nearly 7000 pounds., and I do not think a bear can
have that much strength. I have a jpg of the
bent door if anyone would like to see.

Using yield strength of 50 KSI, I figure about 120 lb of force would
do the job.