Help with calculating and understanding
Bryan Martin wrote:
The unit I will be using is 12V 0.5A
12V X 0.5A = 6 Watts
6W x 24hours = 144 Watts per day
144W / 12V = 12 amp hours
Now given a battery with 110 amp hours
(http://www.defender.com/product.jsp?path=-1|328|51495|306219&id=51496)
We should only draw the battery down 50% so we will actually only get
110 / 2 = 55 amp hours
12 amp hours needed / 55 amp hours available = 4.58 days
so with this battery we have enough juice to potentially run our unit for
4.58 days w/out charging.
Now if the above is not correct then please explain. And the next question
is how would I now figure out approx how large of a panel I would need to
keep the battery charged. I am really looking for the formula and a
understanding of how you got from A to B as oppose to "this panel should
work".
Hi,
In the case of float charging, your charger has to generate higher
output than constant current draw rate plus some + tolerance to
compensate loss. Otherwise the battery will run down eventually.
Also think about winter, summer situation.
Tony
|