On Thu, 14 Aug 2003 02:38:58 GMT, (Kenneth W. Sterling)
wrote:

On Wed, 13 Aug 2003 07:48:52 -0700, Eric R Snow
wrote:

Lets say a fellow winds a coil and puts it under the flywheel of a
magneto ignition motor. How does one determine the number of windings
to get a desired voltage? Also, if no load is put across the windings,
how much drag will it produce? Just looking for a way to power
lighting on a small boat that doesn't require lugging a big battery
around. I saw at the auto parts store that you can now buy LED lights
for your trailer.Probably can get boat ones too. I don't know, but I
think they are supposed to use less current.
Thanks,
Eric
Question I have would be if the boat has a motor/ what kind, and size?
You obviously have access to the flywheel (by removing a cover or
whatever) .
Would it be possible to run an automotive alternator via a rubber
drive wheel or something similar? (you couldn't use a belt as the
ignition coil for the motor is probably mounted externally to the
flywheel OD and it would be in the way).
How many lights would you need? Would a bicycle generator (a better
quality one) work if driven from the motor?
Ken.
Well, the motor is about 3 HP. I don't know yet if the coil is under
the flywheel or outside. It'd be better if mounted outside. Then,
making another coil or two and adding them wouldn't be too much
trouble. Running an auto alternator or even a motorcycle one would
overwhelm the motor. Now, a bicycle generator would probably work.
Didn't think of using a friction drive. The boat is twelve feet long.
The light is really so other boats can see me. Not for searchlights or
anything.
ERS