"Roger" wrote in message
k...
The message
from The Natural Philosopher contains these words:

You do know that incomplete burning of propane to produce CO also
produces
the same amount of hydrogen which could blow your place to bits.

Does the fire authority know you carry out such a potentially dangerous
operation?

Very unlikely. The hydrogen has a far greater affinity for the oxygen
than
the carbon.

So how accurate is the formula dennis@home previously stated?

"C3H8 + 4(O2+4N2) === CO + 2CO2 + 3H2O + H2 + 16 N2"

I am no chemist but ISTM that that could equally well be written as:

C3H8 + 4(O2+4N2) === 2CO + CO2 + 4H2O + 16 N2


That would be correct if there were an ample supply of oxygen.
There isn't so you get the CO and the H2 produced.
The CO reduces the oxides in the glaze (changing the colours).
The hydrogen is left over AFAICT.
This is what may cause an explosion.